Isn't that this thing provided for by GNU date:

If you're sorting or graphing dated data, your raw date values may be represented as seconds since the epoch. But few people can look at the date `946684800' and casually note "Oh, that's the first second of the year 2000."

      date --date='2000-01-01 UTC' +%s
      946684800

To convert such an unwieldy number of seconds back to a more readable form, use a command like this: date -d '1970-01-01 946684800 sec' +"%Y-%m-%d %T %z" 2000-01-01 00:00:00 +0000

On Tue, Jul 19, 2005 at 08:25:53PM +0200, Henrik Stoerner wrote:

On Tue, Jul 19, 2005 at 03:01:39PM -0300, mario andre wrote:

...

Somebody knows how to convert the unix time format to the utc?

This little program will do it:

--- showtime.c --- #include <time.h> #include <stdlib.h> #include <stdio.h>

int main(int argc, char *argv[]) { time_t t = atol(argv[1]);

printf("%s\n", asctime(gmtime(&t)));
return 0;

}

--- end of file ---

Save this as showtime.c, then "cc -o showtime showtime.c". Then you can run "showtime 1121797513" and get "Tue Jul 19 18:25:13 2005"

Henrik

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